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受欢迎的代数 >

1/2 [1+1/4 (3z-1)]=(2z)/3-1/2

解答

\frac{1}{2} [1 + \frac{1}{4} (3 z - 1)] = \frac{2 z}{3} - \frac{1}{2}

解答

z = 3

求解步骤

\frac{1}{2} [1 + \frac{1}{4} (3 z - 1)] = \frac{2 z}{3} - \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

\frac{1 \cdot ( 1 + \frac{1}{4} ( 3 z - 1 ) )}{2} = \frac{2 z}{3} - \frac{1}{2}

1 \cdot (1 + \frac{1}{4} (3 z - 1)) = 1 + \frac{1}{4} (3 z - 1)

\frac{1 + \frac{1}{4} ( 3 z - 1 )}{2} = \frac{2 z}{3} - \frac{1}{2}

将

\frac{2 z}{3}

para o lado esquerdo

\frac{- 7 z + 9}{24} = - \frac{1}{2}

在两边乘以

24

- 7 z + 9 = - 12

将

9

到右边

- 7 z = - 21

两边除以

- 7

z = 3

作图

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