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Frequently Asked Questions (FAQ)
What is (4k^2-12k+9)/(2k^2+19k-33)*(k^2+8k-33)/(k^2-3k) ?
- The solution to (4k^2-12k+9)/(2k^2+19k-33)*(k^2+8k-33)/(k^2-3k) is (2k-3)/k