quadraticformula 2x^2+4x+1=0

解

2 x^{2} + 4 x + 1 = 0

x = \frac{- 2 + 2}{2}, x = - \frac{2 + 1}{2}

十進法表記

x = - 0.29289 \dots, x = - 1.70710 \dots

解答ステップ

2 x^{2} + 4 x + 1 = 0

解くとthe二次式

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

4^{2} - 4 \cdot 2 \cdot 1 = 22

x_{1, 2} = \frac{- 4 \pm 2 2}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 4 + 2 2}{2 \cdot 2}, x_{2} = \frac{- 4 - 2 2}{2 \cdot 2}

x = \frac{- 4 + 2 2}{2 \cdot 2} : \frac{- 2 + 2}{2}

x = \frac{- 4 - 2 2}{2 \cdot 2} : - \frac{2 + 1}{2}

二次equationの解:

x = \frac{- 2 + 2}{2}, x = - \frac{2 + 1}{2}