3n^2+10n=-12-8n^2+10n

解答

3 n^{2} + 10 n = - 12 - 8 n^{2} + 10 n

n = \frac{2 3}{11} i, n = - \frac{2 3}{11} i

求解步骤

3 n^{2} + 10 n = - 12 - 8 n^{2} + 10 n

将

10 n

para o lado esquerdo

3 n^{2} = - 12 - 8 n^{2}

将

8 n^{2}

para o lado esquerdo

11 n^{2} = - 12

两边除以

11

n^{2} = - \frac{12}{11}

对于

x^{2} = f (a)

解为

x = f (a), - f (a)

n = - \frac{12}{11}, n = - - \frac{12}{11}

- \frac{12}{11} = \frac{2 3}{11} i

- - \frac{12}{11} = - \frac{2 3}{11} i

n = \frac{2 3}{11} i, n = - \frac{2 3}{11} i

co m pl e t es q u a re m^{2} + 24 m

2 b^{2} - 3 b + 1 = 0

f a c t or a^{2} x^{2} - 2 a x - 3 = 0

y (\frac{1 + y}{2 - k}) = a

\frac{( x + 2 ) ^{2}}{5} + \frac{( x + 2 ) ^{2}}{3} = \frac{16}{3}