solvefor x,3x^2-2x-4=0

解

x, 3 x^{2} - 2 x - 4 = 0

x = \frac{1 + 13}{3}, x = \frac{1 - 13}{3}

十進法表記

x = 1.53518 \dots, x = - 0.86851 \dots

解答ステップ

3 x^{2} - 2 x - 4 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 4) = 213

x_{1, 2} = \frac{- ( - 2 ) \pm 2 13}{2 \cdot 3}

解を分離する

x_{1} = \frac{- ( - 2 ) + 2 13}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 13}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 13}{2 \cdot 3} : \frac{1 + 13}{3}

x = \frac{- ( - 2 ) - 2 13}{2 \cdot 3} : \frac{1 - 13}{3}

二次equationの解:

x = \frac{1 + 13}{3}, x = \frac{1 - 13}{3}