b^2-5b-50=0

解

b^{2} - 5 b - 50 = 0

b = 10, b = - 5

解答ステップ

b^{2} - 5 b - 50 = 0

解くとthe二次式

b_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 50 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 50) = 15

b_{1, 2} = \frac{- ( - 5 ) \pm 15}{2 \cdot 1}

解を分離する

b_{1} = \frac{- ( - 5 ) + 15}{2 \cdot 1}, b_{2} = \frac{- ( - 5 ) - 15}{2 \cdot 1}

b = \frac{- ( - 5 ) + 15}{2 \cdot 1} : 10

b = \frac{- ( - 5 ) - 15}{2 \cdot 1} : - 5

二次equationの解:

b = 10, b = - 5