solvefor x,4x^2=y^2+z^2

Lösung

löse nach

x, 4 x^{2} = y^{2} + z^{2}

x = \frac{y ^{2} + z ^{2}}{2}, x = - \frac{y ^{2} + z ^{2}}{2}

Schritte zur Lösung

4 x^{2} = y^{2} + z^{2}

Teile beide Seiten durch

4

x^{2} = \frac{y ^{2} + z ^{2}}{4}

Für

x^{2} = f (a)

sind die Lösungen

x = f (a), - f (a)

x = \frac{y ^{2} + z ^{2}}{4}, x = - \frac{y ^{2} + z ^{2}}{4}

Vereinfache

\frac{y ^{2} + z ^{2}}{4} : \frac{y ^{2} + z ^{2}}{2}

Vereinfache

- \frac{y ^{2} + z ^{2}}{4} : - \frac{y ^{2} + z ^{2}}{2}

x = \frac{y ^{2} + z ^{2}}{2}, x = - \frac{y ^{2} + z ^{2}}{2}

\frac{x ^{2}}{8} - \frac{x}{2} = 4

(\frac{1}{2} x + 7)^{2} + 7 (\frac{1}{2} x + 7) + 12 = 0

3 + in (x^{2} + 1) = 2 in (x)

(x + 2) (x + 1) - (x - 1) = 6

0 = - \frac{32}{81} (x^{2} - x - 20)