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受欢迎的代数 >

128=-16t^2+96t

解答

128 = - 16 t^{2} + 96 t

解答

t = 2, t = 4

求解步骤

128 = - 16 t^{2} + 96 t

交换两边

- 16 t^{2} + 96 t = 128

将

128

para o lado esquerdo

- 16 t^{2} + 96 t - 128 = 0

使用求根公式求解

t_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 ( - 16 ) ( - 128 )}{2 ( - 16 )}

9 6^{2} - 4 (- 16) (- 128) = 32

t_{1, 2} = \frac{- 96 \pm 32}{2 ( - 16 )}

将解分隔开

t_{1} = \frac{- 96 + 32}{2 ( - 16 )}, t_{2} = \frac{- 96 - 32}{2 ( - 16 )}

t = \frac{- 96 + 32}{2 ( - 16 )} : 2

t = \frac{- 96 - 32}{2 ( - 16 )} : 4

二次方程组的解是:

t = 2, t = 4

作图

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