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Frequently Asked Questions (FAQ)
What are the solutions to the equation x^2-4x=19 ?
- The solutions to the equation x^2-4x=19 are x=2+sqrt(23),x=2-sqrt(23)
Find the zeros of x^2-4x=19
- The zeros of x^2-4x=19 are x=2+sqrt(23),x=2-sqrt(23)