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受欢迎的代数 >

(x^2+2)/3-(x^2+1)/4 =1-(x+7)/(12)

解答

\frac{x ^{2} + 2}{3} - \frac{x ^{2} + 1}{4} = 1 - \frac{x + 7}{12}

解答

x = 0, x = - 1

求解步骤

\frac{x ^{2} + 2}{3} - \frac{x ^{2} + 1}{4} = 1 - \frac{x + 7}{12}

找到

3, 4, 12

的最小公倍数:

12

乘以最小公倍数=

12

\frac{x ^{2} + 2}{3} \cdot 12 - \frac{x ^{2} + 1}{4} \cdot 12 = 1 \cdot 12 - \frac{x + 7}{12} \cdot 12

化简

4 (x^{2} + 2) - 3 (x^{2} + 1) = 12 - (x + 7)

展开

4 (x^{2} + 2) - 3 (x^{2} + 1) : x^{2} + 5

展开

12 - (x + 7) : - x + 5

x^{2} + 5 = - x + 5

将

5

para o lado esquerdo

x^{2} = - x

将

x

para o lado esquerdo

x^{2} + x = 0

使用求根公式求解

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- 1 + 1}{2 \cdot 1}, x_{2} = \frac{- 1 - 1}{2 \cdot 1}

x = \frac{- 1 + 1}{2 \cdot 1} : 0

x = \frac{- 1 - 1}{2 \cdot 1} : - 1

二次方程组的解是:

x = 0, x = - 1

作图

流行的例子

r (r + 2) = 99

x^2+200x+10000=0

x^{2} + 200 x + 10000 = 0

3 x^{2} + 12 x - 10 = - 3

1/5 x^2+2/5 x+2=0

\frac{1}{5} x^{2} + \frac{2}{5} x + 2 = 0

3x^{(2)}+13=-12x

3 x^{(2)} + 13 = - 12 x