0=x^2+16x+64

解答

0 = x^{2} + 16 x + 64

x = - 8

求解步骤

0 = x^{2} + 16 x + 64

交换两边

x^{2} + 16 x + 64 = 0

使用求根公式求解

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 64 = 0

x_{1, 2} = \frac{- 16 \pm 0}{2 \cdot 1}

x = \frac{- 16}{2 \cdot 1}

\frac{- 16}{2 \cdot 1} = - 8

x = - 8

二次方程组的解是:

x = - 8

N (d) = - 2 d^{2} + 16 d - 14

0.8 x^{2} - 8.16 x + 4.8 = 0

8 x^{2} - 2 x - 21 = 0

so l v e f or a, a^{5} + b^{5} = (a + b) (a^{4} - a^{3} b + a^{2} b^{2} - a b^{3} + b^{4})

so l v e f or q, \frac{1}{4} q^{2} + r = p