solvefor x,x^2-7x+12=0

解

x, x^{2} - 7 x + 12 = 0

x = 4, x = 3

解答ステップ

x^{2} - 7 x + 12 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 12 = 1

x_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 1}

x = \frac{- ( - 7 ) + 1}{2 \cdot 1} : 4

x = \frac{- ( - 7 ) - 1}{2 \cdot 1} : 3

二次equationの解:

x = 4, x = 3