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人気のある代数 >

solvefor p,pqx^2+(p^2-q^2)x=pq

解

解く

p, pq x^{2} + (p^{2} - q^{2}) x = pq

解

p = \frac{q}{x}, p = - x q; x \neq = 0

解答ステップ

pq x^{2} + (p^{2} - q^{2}) x = pq

拡張

pq x^{2} + (p^{2} - q^{2}) x : x^{2} pq + x p^{2} - x q^{2}

x^{2} pq + x p^{2} - x q^{2} = pq

pq

を左側に移動します

x^{2} pq + x p^{2} - x q^{2} - pq = 0

標準的な形式で書く

a x^{2} + b x + c = 0

x p^{2} + (x^{2} q - q) p - x q^{2} = 0

解くとthe二次式

p_{1, 2} = \frac{- ( x ^{2} q - q ) \pm ( x ^{2} q - q ) ^{2} - 4 x ( - x q ^{2} )}{2 x}

簡素化

(x^{2} q - q)^{2} - 4 x (- x q^{2}) : q (x^{2} + 1)

p_{1, 2} = \frac{- ( x ^{2} q - q ) \pm q ( x ^{2} + 1 )}{2 x}; x \neq = 0

解を分離する

p_{1} = \frac{- ( x ^{2} q - q ) + q ( x ^{2} + 1 )}{2 x}, p_{2} = \frac{- ( x ^{2} q - q ) - q ( x ^{2} + 1 )}{2 x}

p = \frac{- ( x ^{2} q - q ) + q ( x ^{2} + 1 )}{2 x} : \frac{q}{x}

p = \frac{- ( x ^{2} q - q ) - q ( x ^{2} + 1 )}{2 x} : - x q

二次equationの解:

p = \frac{q}{x}, p = - x q; x \neq = 0

グラフ

人気の例

12x^2-224x+703=0

12 x^{2} - 224 x + 703 = 0

solvefor a,(a+b)^2=81

so l v e f or a, (a + b)^{2} = 81

4 = (x + 2)^{2}

2 x - 1 = x^{2} - 4 x + 4

x^{2} - 18 x + 64 = 0