2y^2-8y=0

解答

2 y^{2} - 8 y = 0

y = 4, y = 0

求解步骤

2 y^{2} - 8 y = 0

使用求根公式求解

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 0 = 8

y_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 2}

将解分隔开

y_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 2}, y_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 2}

y = \frac{- ( - 8 ) + 8}{2 \cdot 2} : 4

y = \frac{- ( - 8 ) - 8}{2 \cdot 2} : 0

二次方程组的解是:

y = 4, y = 0

5 x^{2} + 2 = x

co m pl e t es q u a re x^{2} + 8 x - 3 = 0

24 = x^{2}

\frac{1}{3} x^{2} + \frac{x}{2} - \frac{1}{3} = 0

- 6 - 3 x + 3 x^{2} - 4 x - 8 - 9 x - 4 = - 2 x^{2} + 3 x^{2}