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受欢迎的代数 >

b^2-10b-24=0

解答

b^{2} - 10 b - 24 = 0

解答

b = 12, b = - 2

求解步骤

b^{2} - 10 b - 24 = 0

使用求根公式求解

b_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 24) = 14

b_{1, 2} = \frac{- ( - 10 ) \pm 14}{2 \cdot 1}

将解分隔开

b_{1} = \frac{- ( - 10 ) + 14}{2 \cdot 1}, b_{2} = \frac{- ( - 10 ) - 14}{2 \cdot 1}

b = \frac{- ( - 10 ) + 14}{2 \cdot 1} : 12

b = \frac{- ( - 10 ) - 14}{2 \cdot 1} : - 2

二次方程组的解是:

b = 12, b = - 2

作图

流行的例子

(2 - 5 t)^{2} = 12

x^{2} + 7 x + 12 = 2

4-(10x+1)/6 =4x(16x+3)/4

4 - \frac{10 x + 1}{6} = 4 x \frac{16 x + 3}{4}

- 2 x^{2} + 9 x + 18 = 0

4=a(2-h)^2+k,-4=a(-2-h)^2+k,5=a(1-h)^2+k

4 = a (2 - h)^{2} + k, - 4 = a (- 2 - h)^{2} + k, 5 = a (1 - h)^{2} + k