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受欢迎的代数 >

(x-2)^2+3(3x-4)(3x+4)=7(4x-3)-23

解答

(x - 2)^{2} + 3 (3 x - 4) (3 x + 4) = 7 (4 x - 3) - 23

解答

x = \frac{8}{7}, x = 0

+1

十进制

x = 1.14285 \dots, x = 0

求解步骤

(x - 2)^{2} + 3 (3 x - 4) (3 x + 4) = 7 (4 x - 3) - 23

展开

(x - 2)^{2} + 3 (3 x - 4) (3 x + 4) : 28 x^{2} - 4 x - 44

展开

7 (4 x - 3) - 23 : 28 x - 44

28 x^{2} - 4 x - 44 = 28 x - 44

将

44

para o lado esquerdo

28 x^{2} - 4 x = 28 x

将

28 x

para o lado esquerdo

28 x^{2} - 32 x = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 28 \cdot 0}{2 \cdot 28}

(- 32)^{2} - 4 \cdot 28 \cdot 0 = 32

x_{1, 2} = \frac{- ( - 32 ) \pm 32}{2 \cdot 28}

将解分隔开

x_{1} = \frac{- ( - 32 ) + 32}{2 \cdot 28}, x_{2} = \frac{- ( - 32 ) - 32}{2 \cdot 28}

x = \frac{- ( - 32 ) + 32}{2 \cdot 28} : \frac{8}{7}

x = \frac{- ( - 32 ) - 32}{2 \cdot 28} : 0

二次方程组的解是:

x = \frac{8}{7}, x = 0

作图

流行的例子

2 x^{2} - 13 x + 2 = 0

completesquare x^2-10x=0

co m pl e t es q u a re x^{2} - 10 x = 0

completesquare 3x^2-4x=0

co m pl e t es q u a re 3 x^{2} - 4 x = 0

solvefor y,x^2+y^2=16

so l v e f or y, x^{2} + y^{2} = 16

(x + 4) (x + 2) = 15