-12x^2+12x+144=0

解答

- 12 x^{2} + 12 x + 144 = 0

x = - 3, x = 4

求解步骤

- 12 x^{2} + 12 x + 144 = 0

使用求根公式求解

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 12 ) \cdot 144}{2 ( - 12 )}

1 2^{2} - 4 (- 12) \cdot 144 = 84

x_{1, 2} = \frac{- 12 \pm 84}{2 ( - 12 )}

将解分隔开

x_{1} = \frac{- 12 + 84}{2 ( - 12 )}, x_{2} = \frac{- 12 - 84}{2 ( - 12 )}

x = \frac{- 12 + 84}{2 ( - 12 )} : - 3

x = \frac{- 12 - 84}{2 ( - 12 )} : 4

二次方程组的解是:

x = - 3, x = 4

so l v e f or x, 6 x^{2} + 6 = 4 k x

3 x (x - 4) = (x - 3) (x - 3)

- 4 y - 2 y^{2} = - 16

3 x^{2} = - 75

(3 x + 1) (2 x - 1) = 0