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受欢迎的代数 >

x^2+ax+1=0

解答

x^{2} + a x + 1 = 0

解答

x = \frac{- a + a ^{2} - 4}{2}, x = \frac{- a - a ^{2} - 4}{2}

求解步骤

x^{2} + a x + 1 = 0

使用求根公式求解

x_{1, 2} = \frac{- a \pm a ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

化简

a^{2} - 4 \cdot 1 \cdot 1 : a^{2} - 4

x_{1, 2} = \frac{- a \pm a ^{2} - 4}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- a + a ^{2} - 4}{2 \cdot 1}, x_{2} = \frac{- a - a ^{2} - 4}{2 \cdot 1}

x = \frac{- a + a ^{2} - 4}{2 \cdot 1} : \frac{- a + a ^{2} - 4}{2}

x = \frac{- a - a ^{2} - 4}{2 \cdot 1} : \frac{- a - a ^{2} - 4}{2}

二次方程组的解是:

x = \frac{- a + a ^{2} - 4}{2}, x = \frac{- a - a ^{2} - 4}{2}

作图

流行的例子

(x + 1)^{2} = - 121

x^{2} + 21 x + 20 = 0

x^{2} + 11 x + 5 = 0

solvefor x,7x-y+3xy=x^2+y^2

so l v e f or x, 7 x - y + 3 x y = x^{2} + y^{2}

(4+x)(5-2x)=(2x+1)(x-2)

(4 + x) (5 - 2 x) = (2 x + 1) (x - 2)