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Beliebt Algebra >

faktorisieren 25x^6-16y^2

Lösung

faktorisieren

25 x^{6} - 16 y^{2}

Lösung

(5 x^{3} + 4 y) (5 x^{3} - 4 y)

Schritte zur Lösung

25 x^{6} - 16 y^{2}

25 x^{6} = (5 x^{3})^{2}

16 y^{2} = (4 y)^{2}

= (5 x^{3})^{2} - (4 y)^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(5 x^{3})^{2} - (4 y)^{2} = (5 x^{3} + 4 y) (5 x^{3} - 4 y)

= (5 x^{3} + 4 y) (5 x^{3} - 4 y)

Beliebte Beispiele

(x^2-2x-2}{x^2-3x}+(7x-19)/(x-3)<= \frac{8x+1)/x

\frac{x ^{2} - 2 x - 2}{x ^{2} - 3 x} + \frac{7 x - 19}{x - 3} \leq \frac{8 x + 1}{x}

\frac{5}{6} v < \frac{8}{5}

p^{2} - 4 p + 4 = 0

∣ 2 b - 23 ∣ \geq - 15

5 < x \leq 7