簡約 40000(1+((0.12)/4))^{-(4(3))}

解

簡約

40000 (1 + (\frac{0.12}{4}))^{- (4 (3))}

\frac{40000 \cdot 10 0 ^{12}}{10 3 ^{12}}

十進法表記

28055.19520 \dots

解答ステップ

40000 (1 + (\frac{0.12}{4}))^{- (4 (3))}

(1 + (\frac{0.12}{4}))^{- (4 (3))} = (1 + \frac{0.12}{4})^{- 4 \cdot 3}

= 40000 (1 + \frac{0.12}{4})^{- 4 \cdot 3}

指数の規則を適用する:

a^{- b} = \frac{1}{a ^{b}}

(1 + \frac{0.12}{4})^{- 4 \cdot 3} = \frac{1}{( 1 + \frac{0.12}{4} ) ^{4 \cdot 3}}

= 40000 \cdot \frac{1}{( 1 + \frac{0.12}{4} ) ^{4 \cdot 3}}

(1 + \frac{0.12}{4})^{4 \cdot 3} = \frac{10 3 ^{12}}{10 0 ^{12}}

= 40000 \cdot \frac{1}{\frac{10 3 ^{12}}{10 0 ^{12}}}

分数の規則を適用する:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= 40000 \cdot \frac{10 0 ^{12}}{10 3 ^{12}}

40000 \cdot \frac{10 0 ^{12}}{10 3 ^{12}} = \frac{40000 \cdot 10 0 ^{12}}{10 3 ^{12}}

= \frac{40000 \cdot 10 0 ^{12}}{10 3 ^{12}}