What is 2te^{-2t}sin(2t)u_{s}(t) ?

The solution to 2te^{-2t}sin(2t)u_{s}(t) is 2e^{-2t}t^2u_{s}sin(2t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 2te^{-2t}sin(2t)u_{s}(t)

simplify

2 t e^{- 2 t} sin (2 t) u_{s} (t)

2 e^{- 2 t} t^{2} u_{s} sin (2 t)

Solution steps

2 t e^{- 2 t} sin (2 t) u_{s} (t)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

tt = t^{1 + 1}

= 2 e^{- 2 t} sin (2 t) u_{s} t^{1 + 1}

Add the numbers:

1 + 1 = 2

= 2 e^{- 2 t} sin (2 t) u_{s} t^{2}

(- 1)^{n} \cdot x^{n}

a^{\frac{16}{15}}

3.9 e^{- 0.2 (210)}

x + y

1.5 \cdot 1 0^{- 6} \cdot 12

What is 2te^{-2t}sin(2t)u_{s}(t) ?
The solution to 2te^{-2t}sin(2t)u_{s}(t) is 2e^{-2t}t^2u_{s}sin(2t)