What is (\sqrt[3]{3a^4})/(\sqrt[3]{7b^2)} ?

The solution to (\sqrt[3]{3a^4})/(\sqrt[3]{7b^2)} is (\sqrt[3]{3}a\sqrt[3]{a})/(\sqrt[3]{7b^2)}

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simplify (\sqrt[3]{3a^4})/(\sqrt[3]{7b^2)}

simplify

\frac{3 3 a ^{4}}{3 7 b ^{2}}

\frac{3 3 a 3 a}{3 7 b ^{2}}

Solution steps

\frac{3 3 a ^{4}}{3 7 b ^{2}}

Apply radical rule:

n ab = n a n b,

assuming

a \geq 0, b \geq 0

3 3 a^{4} = 33 3 a^{4}

= \frac{3 3 3 a ^{4}}{3 7 b ^{2}}

Simplify

3 a^{4} : a 3 a

= \frac{3 3 a 3 a}{3 7 b ^{2}}

\frac{4 2}{4 27}

3 3^{3}

(7 x^{\frac{1}{3}}) (2 x^{\frac{1}{4}})

\frac{n ^{8}}{( n + 1 ) ^{8}}

x^{4} (4 x^{3} y^{3})

What is (\sqrt[3]{3a^4})/(\sqrt[3]{7b^2)} ?
The solution to (\sqrt[3]{3a^4})/(\sqrt[3]{7b^2)} is (\sqrt[3]{3}a\sqrt[3]{a})/(\sqrt[3]{7b^2)}