What is e^{-(x^2+y^2+z^2)^{3/2}} ?

The solution to e^{-(x^2+y^2+z^2)^{3/2}} is 1/(e^{(x^2+y^2+z^2)^{3/2)}}

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simplify e^{-(x^2+y^2+z^2)^{3/2}}

simplify

e^{- (x^{2} + y^{2} + z^{2})^{\frac{3}{2}}}

\frac{1}{e ^{(x^{2} + y^{2} + z^{2})^{\frac{3}{2}}}}

Solution steps

e^{- (x^{2} + y^{2} + z^{2})^{\frac{3}{2}}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{(x^{2} + y^{2} + z^{2})^{\frac{3}{2}}}}

\frac{x - 1}{4 - x}

\frac{( x - 1 ) ^{2}}{( x + 1 ) ^{2}}

4 π \times 1 0^{- 7}

\frac{3 6 x ^{2}}{3 5 y}

(43) (23)

What is e^{-(x^2+y^2+z^2)^{3/2}} ?
The solution to e^{-(x^2+y^2+z^2)^{3/2}} is 1/(e^{(x^2+y^2+z^2)^{3/2)}}