What is e^{-2t}cos(3t)u(t) ?

The solution to e^{-2t}cos(3t)u(t) is (tucos(3t))/(e^{2t)}

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simplify e^{-2t}cos(3t)u(t)

simplify

e^{- 2 t} cos (3 t) u (t)

\frac{t u cos ( 3 t )}{e ^{2 t}}

Solution steps

e^{- 2 t} cos (3 t) u (t)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 t}} t u cos (3 t)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot cos ( 3 t ) u t}{e ^{2 t}}

Multiply:

1 \cdot cos (3 t) = cos (3 t)

= \frac{t u cos ( 3 t )}{e ^{2 t}}

(21 - 27)^{2}

6 (1 + 3)^{- 2}

- (x + 1)^{2} (x - 1)^{2}

(x + 2)^{3}

(- 81)^{- \frac{3}{2}}

What is e^{-2t}cos(3t)u(t) ?
The solution to e^{-2t}cos(3t)u(t) is (tucos(3t))/(e^{2t)}