What is (x+arctan(e^x+sin(x)))^{-1} ?

The solution to (x+arctan(e^x+sin(x)))^{-1} is 1/(x+arctan(e^x+sin(x)))

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simplify (x+arctan(e^x+sin(x)))^{-1}

simplify

(x + arctan (e^{x} + sin (x)))^{- 1}

\frac{1}{x + arctan ( e ^{x} + sin ( x ) )}

Solution steps

(x + arctan (e^{x} + sin (x)))^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{( x + arctan ( e ^{x} + sin ( x ) ) )}

Remove parentheses:

(a) = a

= \frac{1}{x + arctan ( e ^{x} + sin ( x ) )}

x^{2} (x^{2} + 5)^{2}

(x + 1)^{2} (x - 3)^{2}

(1 + 2 x)^{- \frac{1}{2}}

(611) (511)

(3 y^{6}) (27 y)

What is (x+arctan(e^x+sin(x)))^{-1} ?
The solution to (x+arctan(e^x+sin(x)))^{-1} is 1/(x+arctan(e^x+sin(x)))