t^2-6t-16=0

解

t^{2} - 6 t - 16 = 0

t = 8, t = - 2

解答ステップ

t^{2} - 6 t - 16 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 16) = 10

t_{1, 2} = \frac{- ( - 6 ) \pm 10}{2 \cdot 1}

解を分離する

t_{1} = \frac{- ( - 6 ) + 10}{2 \cdot 1}, t_{2} = \frac{- ( - 6 ) - 10}{2 \cdot 1}

t = \frac{- ( - 6 ) + 10}{2 \cdot 1} : 8

t = \frac{- ( - 6 ) - 10}{2 \cdot 1} : - 2

二次equationの解:

t = 8, t = - 2