What is expand ((4z-7)^4)/(80) ?

The solution to expand ((4z-7)^4)/(80) is (16z^4)/5-(112z^3)/5+(294z^2)/5-(343z)/5+2401/80

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expand ((4z-7)^4)/(80)

expand

\frac{( 4 z - 7 ) ^{4}}{80}

\frac{16 z ^{4}}{5} - \frac{112 z ^{3}}{5} + \frac{294 z ^{2}}{5} - \frac{343 z}{5} + \frac{2401}{80}

Solution steps

\frac{( 4 z - 7 ) ^{4}}{80}

(4 z - 7)^{4} = 256 z^{4} - 1792 z^{3} + 4704 z^{2} - 5488 z + 2401

= \frac{256 z ^{4} - 1792 z ^{3} + 4704 z ^{2} - 5488 z + 2401}{80}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{256 z ^{4} - 1792 z ^{3} + 4704 z ^{2} - 5488 z + 2401}{80} = \frac{256 z ^{4}}{80} - \frac{1792 z ^{3}}{80} + \frac{4704 z ^{2}}{80} - \frac{5488 z}{80} + \frac{2401}{80}

= \frac{256 z ^{4}}{80} - \frac{1792 z ^{3}}{80} + \frac{4704 z ^{2}}{80} - \frac{5488 z}{80} + \frac{2401}{80}

\frac{256 z ^{4}}{80} = \frac{16 z ^{4}}{5}

\frac{1792 z ^{3}}{80} = \frac{112 z ^{3}}{5}

\frac{4704 z ^{2}}{80} = \frac{294 z ^{2}}{5}

\frac{5488 z}{80} = \frac{343 z}{5}

= \frac{16 z ^{4}}{5} - \frac{112 z ^{3}}{5} + \frac{294 z ^{2}}{5} - \frac{343 z}{5} + \frac{2401}{80}

\frac{1}{4} (- 2 e^{- 2 x} x - e^{- 2 x})

3 x y^{2} y^{'} (x) + y^{3} (1 + x^{6} y^{2})

(x + Δ x)^{10}

\frac{5 x ^{2} + 8 x - 7}{( x + 2 ) ( x ^{2} + x + 1 )}

\frac{8}{15 ( s - 2 )}

What is expand ((4z-7)^4)/(80) ?
The solution to expand ((4z-7)^4)/(80) is (16z^4)/5-(112z^3)/5+(294z^2)/5-(343z)/5+2401/80