erweitern ((x-3)^2)/3

Lösung

erweitern

\frac{( x - 3 ) ^{2}}{3}

\frac{x ^{2}}{3} - 2 x + 3

Schritte zur Lösung

\frac{( x - 3 ) ^{2}}{3}

(x - 3)^{2} = x^{2} - 6 x + 9

= \frac{x ^{2} - 6 x + 9}{3}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 6 x + 9}{3} = \frac{x ^{2}}{3} - \frac{6 x}{3} + \frac{9}{3}

= \frac{x ^{2}}{3} - \frac{6 x}{3} + \frac{9}{3}

Teile die Zahlen:

\frac{6}{3} = 2

= \frac{x ^{2}}{3} - 2 x + \frac{9}{3}

Teile die Zahlen:

\frac{9}{3} = 3

= \frac{x ^{2}}{3} - 2 x + 3

e x p an d (1 + 1 - x^{2}) (1 + \frac{x ^{2}}{1 - x ^{2}})

e x p an d (e^{4 x}) (x^{2} \frac{d y}{d x} + 2 x y)

e x p an d \frac{1}{( A \cdot x ^{2} + 1 ) \cdot x ^{2}}

\frac{d}{d t} ((a (t)) (a (t)^{4} + t^{4} - 6 a (t)^{2} t))

e x p an d \frac{j + 2}{( - 2 + j ) ( j - 1 ) ( j ^{2} + 2 j + 5 )}