What is expand (2x^2-4x+9)/((2-x)(x+3)) ?

The solution to expand (2x^2-4x+9)/((2-x)(x+3)) is (2x^2-4x+9)/(-x-x^2+6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x^2-4x+9)/((2-x)(x+3))

expand

\frac{2 x ^{2} - 4 x + 9}{( 2 - x ) ( x + 3 )}

\frac{2 x ^{2} - 4 x + 9}{- x - x ^{2} + 6}

Solution steps

\frac{2 x ^{2} - 4 x + 9}{( 2 - x ) ( x + 3 )}

Expand

(2 - x) (x + 3) : - x - x^{2} + 6

= \frac{2 x ^{2} - 4 x + 9}{- x - x ^{2} + 6}

((y + x y^{3}) d x + x d y = 0) \frac{3}{y}

A (3, - 3) y B (- 1, - 1)

(- 3 - 4 i)^{6}

\frac{3 x + 5}{( 6 x + 2 ) ( x - 4 )}

(- 3 - 4 i)^{5}

What is expand (2x^2-4x+9)/((2-x)(x+3)) ?
The solution to expand (2x^2-4x+9)/((2-x)(x+3)) is (2x^2-4x+9)/(-x-x^2+6)