What is expand 1/(x^3)((dy)/(dx)-3/x y=x^4) ?

The solution to expand 1/(x^3)((dy)/(dx)-3/x y=x^4) is (\frac{dy)/(dx)}{x^3}-(3y)/(x^4)=x^4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/(x^3)((dy)/(dx)-3/x y=x^4)

expand

\frac{1}{x ^{3}} (\frac{d y}{d x} - \frac{3}{x} y = x^{4})

\frac{\frac{d y}{d x}}{x ^{3}} - \frac{3 y}{x ^{4}} = x^{4}

Solution steps

\frac{1}{x ^{3}} (\frac{d y}{d x} - \frac{3}{x} y = x^{4})

= \frac{1}{x ^{3}} (\frac{d y}{d x} - = \frac{3}{x} x^{4} y)

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{1}{x ^{3}}, b = \frac{d y}{d x}, c = \frac{3}{x} y = x^{4}

\frac{1}{x ^{3}} \frac{d y}{d x} - \frac{1}{x ^{3}} \cdot \frac{3}{x} y = x^{4}

Expand

\frac{1}{x ^{3}} \frac{d y}{d x} - \frac{1}{x ^{3}} \cdot \frac{3}{x} y : \frac{\frac{d y}{d x}}{x ^{3}} - \frac{3 y}{x ^{4}}

\frac{\frac{d y}{d x}}{x ^{3}} - \frac{3 y}{x ^{4}} = x^{4}

(x + 2 i)^{4}

10 (x + Δ x)^{2}

(x + 2 i)^{3}

\frac{2 ( x ^{4} - 3 x ^{2} )}{( x ^{2} - 1 ) ^{2}}

\frac{1}{( 3 + n ) ^{2}}

What is expand 1/(x^3)((dy)/(dx)-3/x y=x^4) ?
The solution to expand 1/(x^3)((dy)/(dx)-3/x y=x^4) is (\frac{dy)/(dx)}{x^3}-(3y)/(x^4)=x^4