What is expand ((+4s^2-3s-1)(2s+2))/s ?

The solution to expand ((+4s^2-3s-1)(2s+2))/s is 8s^2+2s-8-2/s

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expand ((+4s^2-3s-1)(2s+2))/s

expand

\frac{( + 4 s ^{2} - 3 s - 1 ) ( 2 s + 2 )}{s}

8 s^{2} + 2 s - 8 - \frac{2}{s}

Solution steps

\frac{( 4 s ^{2} - 3 s - 1 ) ( 2 s + 2 )}{s}

Expand

(4 s^{2} - 3 s - 1) (2 s + 2) : 8 s^{3} + 2 s^{2} - 8 s - 2

= \frac{8 s ^{3} + 2 s ^{2} - 8 s - 2}{s}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{8 s ^{3} + 2 s ^{2} - 8 s - 2}{s} = \frac{8 s ^{3}}{s} + \frac{2 s ^{2}}{s} - \frac{8 s}{s} - \frac{2}{s}

= \frac{8 s ^{3}}{s} + \frac{2 s ^{2}}{s} - \frac{8 s}{s} - \frac{2}{s}

Cancel

\frac{8 s ^{3}}{s} : 8 s^{2}

= 8 s^{2} + \frac{2 s ^{2}}{s} - \frac{8 s}{s} - \frac{2}{s}

Cancel

\frac{2 s ^{2}}{s} : 2 s

= 8 s^{2} + 2 s - \frac{8 s}{s} - \frac{2}{s}

Cancel

\frac{8 s}{s} : 8

= 8 s^{2} + 2 s - 8 - \frac{2}{s}

6 (9 + 2)

\frac{( π \cdot ( 3 \cdot x - 3 x ) )}{3}

2 z (e^{x yz} x yz + e^{x yz})

(x + 2) (\frac{22}{x} + 2)

- \frac{10}{( x - 2 ) ^{3}}

What is expand ((+4s^2-3s-1)(2s+2))/s ?
The solution to expand ((+4s^2-3s-1)(2s+2))/s is 8s^2+2s-8-2/s