展开 (s^3+3s^2+2s-1)/((s+2)^3(s+1))

解答

展开

\frac{s ^{3} + 3 s ^{2} + 2 s - 1}{( s + 2 ) ^{3} ( s + 1 )}

\frac{s ^{3} + 3 s ^{2} + 2 s - 1}{s ^{4} + 7 s ^{3} + 18 s ^{2} + 20 s + 8}

求解步骤

\frac{s ^{3} + 3 s ^{2} + 2 s - 1}{( s + 2 ) ^{3} ( s + 1 )}

(s + 2)^{3} = s^{3} + 6 s^{2} + 12 s + 8

= \frac{s ^{3} + 3 s ^{2} + 2 s - 1}{( s ^{3} + 6 s ^{2} + 12 s + 8 ) ( s + 1 )}

乘开

(s^{3} + 6 s^{2} + 12 s + 8) (s + 1) : s^{4} + 7 s^{3} + 18 s^{2} + 20 s + 8

= \frac{s ^{3} + 3 s ^{2} + 2 s - 1}{s ^{4} + 7 s ^{3} + 18 s ^{2} + 20 s + 8}

s im pl i f y (a - 7 x) \cdot (a + 7 x)

e x p an d \frac{( ( 2 x - 1 ) e ^{\frac{1}{x}} )}{5}

e x p an d \frac{5 ( 2 v - u ^{2} )}{u ^{3} v ^{3}}

e x p an d x^{2} \cdot (g 3 x + 1)

s im pl i f y (x - 1 + 32) (x - 1 - 32)