What is expand (2x^2+10x-3)/((x+1)(x^2-9)) ?

The solution to expand (2x^2+10x-3)/((x+1)(x^2-9)) is (2x^2+10x-3)/(x^3-9x+x^2-9)

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expand (2x^2+10x-3)/((x+1)(x^2-9))

expand

\frac{2 x ^{2} + 10 x - 3}{( x + 1 ) ( x ^{2} - 9 )}

\frac{2 x ^{2} + 10 x - 3}{x ^{3} - 9 x + x ^{2} - 9}

Solution steps

\frac{2 x ^{2} + 10 x - 3}{( x + 1 ) ( x ^{2} - 9 )}

Expand

(x + 1) (x^{2} - 9) : x^{3} - 9 x + x^{2} - 9

= \frac{2 x ^{2} + 10 x - 3}{x ^{3} - 9 x + x ^{2} - 9}

(z + i)^{2} \cdot (z - 1)

e^{- 2 x} (x^{2} + x + 1) - 0.5

\frac{d ^{2}}{d ^{2} x} (x^{3} + y^{3} = 16)

\frac{sin ( x ) + cos ^{2} ( x )}{( 1 - sin ( x ) ) ^{2}}

11.18 - (5 + y) y (\frac{( ( 5 + y ) y )}{5 + 2.83 y})^{\frac{2}{3}}

What is expand (2x^2+10x-3)/((x+1)(x^2-9)) ?
The solution to expand (2x^2+10x-3)/((x+1)(x^2-9)) is (2x^2+10x-3)/(x^3-9x+x^2-9)