erweitern (2u^2+2v^2)sqrt(2u^2+2v^2+4)

Lösung

erweitern

(2 u^{2} + 2 v^{2}) 2 u^{2} + 2 v^{2} + 4

2 u^{2} 2 u^{2} + 2 v^{2} + 4 + 2 v^{2} 2 u^{2} + 2 v^{2} + 4

Schritte zur Lösung

(2 u^{2} + 2 v^{2}) 2 u^{2} + 2 v^{2} + 4

= 2 u^{2} + 2 v^{2} + 4 (2 u^{2} + 2 v^{2})

Wende das Distributivgesetz an:

a (b + c) = ab + a c

2 u^{2} + 2 v^{2} + 4 (2 u^{2} + 2 v^{2}) = 2 u^{2} + 2 v^{2} + 4 \cdot 2 u^{2} + 2 u^{2} + 2 v^{2} + 4 \cdot 2 v^{2}

= 2 u^{2} + 2 v^{2} + 4 \cdot 2 u^{2} + 2 u^{2} + 2 v^{2} + 4 \cdot 2 v^{2}

= 2 u^{2} 2 u^{2} + 2 v^{2} + 4 + 2 v^{2} 2 u^{2} + 2 v^{2} + 4

s im pl i f y (3 - 1 - 4 x) (3 + 1 - 4 x)

e x p an d (4 + sin (θ))^{2}

e x p an d lo g_{10} (3 \frac{x}{z})

s im pl i f y (x + \frac{2}{5}) (12 x^{2} - 12 x^{3})

e x p an d e^{t} (e^{- t} t - 2 e^{- t})