展開する solve(x-2)(x+3)(x^2-4x-1)

解

展開する

so l v e (x - 2) (x + 3) (x^{2} - 4 x - 1)

e l so v x^{4} - 3 e l so v x^{3} - 11 e l so v x^{2} + 23 e l so vx + 6 e l so v

解答ステップ

so l v e (x - 2) (x + 3) (x^{2} - 4 x - 1)

= e l so v (x - 2) (x + 3) (x^{2} - 4 x - 1)

拡張

(x - 2) (x + 3) : x^{2} + x - 6

= so l v e (x^{2} + x - 6) (x^{2} - 4 x - 1)

拡張

(x^{2} + x - 6) (x^{2} - 4 x - 1) : x^{4} - 3 x^{3} - 11 x^{2} + 23 x + 6

= so l v e (x^{4} - 3 x^{3} - 11 x^{2} + 23 x + 6)

拡張

so l v e (x^{4} - 3 x^{3} - 11 x^{2} + 23 x + 6) : e l so v x^{4} - 3 e l so v x^{3} - 11 e l so v x^{2} + 23 e l so vx + 6 e l so v

= e l so v x^{4} - 3 e l so v x^{3} - 11 e l so v x^{2} + 23 e l so vx + 6 e l so v