展开 (\partial)/(\partial x)(kx(1-y))-ax^2

解答

展开

\frac{\partial}{\partial x} (k x (1 - y)) - a x^{2}

\frac{\partial}{\partial x} (k x - k x y) - a x^{2}

求解步骤

\frac{\partial}{\partial x} (k x (1 - y)) - a x^{2}

乘开

k x (1 - y) : k x - k x y

= \frac{\partial}{\partial x} (k x - k x y) - a x^{2}

e x p an d 8 (- 4 k - 1 + 3 = - 5 - 32 k)

s im pl i f y (- \frac{1}{x ^{2}} + \frac{12}{x ^{4}}) (x^{3} - 5 x - 1)

e x p an d cos (3 t - 3) u (t - 1) + t^{3} u (t - 2)

\frac{d}{d r ( T )} ((E (r, T)) (10 - (10 T) (b^{- 0.14 r (T)})))

e x p an d \frac{x ^{3} - 3 x ^{2}}{( x - 1 ) ^{3}}