化简 (-b+sqrt(b^2+4ac))^2

解答

化简

(- b + b^{2} + 4 a c)^{2}

2 b^{2} - 2 b b^{2} + 4 a c + 4 a c

求解步骤

(- b + b^{2} + 4 a c)^{2}

使用完全平方公式:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(- b + b^{2} + 4 a c)^{2} = (- b)^{2} + 2 (- b) b^{2} + 4 a c + (b^{2} + 4 a c)^{2}

= (- b)^{2} + 2 (- b) b^{2} + 4 a c + (b^{2} + 4 a c)^{2}

化简

(- b)^{2} + 2 (- b) b^{2} + 4 a c + (b^{2} + 4 a c)^{2} : 2 b^{2} - 2 b b^{2} + 4 a c + 4 a c

= 2 b^{2} - 2 b b^{2} + 4 a c + 4 a c

e x p an d \frac{1}{( 2 x )} 5

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