展開する-2(x+1)sin^2(x+1)

解

展開する

- 2 (x + 1) sin^{2} (x + 1)

- 2 x sin^{2} (x + 1) - 2 sin^{2} (x + 1)

解答ステップ

- 2 (x + 1) sin^{2} (x + 1)

= - 2 sin^{2} (x + 1) (x + 1)

分配法則を適用する:

a (b + c) = ab + a c

- 2 sin^{2} (x + 1) (x + 1) = - 2 sin^{2} (x + 1) x - 2 sin^{2} (x + 1) \cdot 1

= - 2 sin^{2} (x + 1) x - 2 sin^{2} (x + 1) \cdot 1

簡素化

- 2 sin^{2} (x + 1) x - 2 sin^{2} (x + 1) \cdot 1 : - 2 x sin^{2} (x + 1) - 2 sin^{2} (x + 1)

= - 2 x sin^{2} (x + 1) - 2 sin^{2} (x + 1)