erweitern (4(3x^3-1))/((1+x^2)^3)

Lösung

erweitern

\frac{4 ( 3 x ^{3} - 1 )}{( 1 + x ^{2} ) ^{3}}

\frac{12 x ^{3} - 4}{1 + 3 x ^{2} + 3 x ^{4} + x ^{6}}

Schritte zur Lösung

\frac{4 ( 3 x ^{3} - 1 )}{( 1 + x ^{2} ) ^{3}}

(1 + x^{2})^{3} = 1 + 3 x^{2} + 3 x^{4} + x^{6}

= \frac{4 ( 3 x ^{3} - 1 )}{1 + 3 x ^{2} + 3 x ^{4} + x ^{6}}

Multipliziere aus

4 (3 x^{3} - 1) : 12 x^{3} - 4

= \frac{12 x ^{3} - 4}{1 + 3 x ^{2} + 3 x ^{4} + x ^{6}}

e x p an d \frac{s ^{2} + 3}{s ( s + 2 ) ^{2} ( s + 1 )}

e x p an d \frac{3 x ^{3} - x ^{2} + 6 x - 4}{( x ^{2} + 1 ) ( x ^{2} + 2 )}

e x p an d (x^{\frac{1}{3}} - \frac{2}{3})^{6}

e x p an d \frac{- 2 x ^{2} + 1}{( x ^{2} + 1 ) ^{\frac{5}{2}}}

e x p an d \frac{1}{s ^{2} ( s + 3 ) ^{2}}