展开 (pi+pie^{-s})/((s^2+pi^2)(s^2+9))

解答

展开

\frac{π + π e ^{- s}}{( s ^{2} + π ^{2} ) ( s ^{2} + 9 )}

\frac{π + π e ^{- s}}{s ^{4} + 9 s ^{2} + π ^{2} s ^{2} + 9 π ^{2}}

求解步骤

\frac{π + π e ^{- s}}{( s ^{2} + π ^{2} ) ( s ^{2} + 9 )}

乘开

(s^{2} + π^{2}) (s^{2} + 9) : s^{4} + 9 s^{2} + π^{2} s^{2} + 9 π^{2}

= \frac{π + π e ^{- s}}{s ^{4} + 9 s ^{2} + π ^{2} s ^{2} + 9 π ^{2}}

e x p an d (3 \cdot sin (20 π t) + sin (30 π t)) \cdot sin (100 π t)

s im pl i f y (2 - 7) 2

e x p an d \frac{5}{( x + 3 ) ^{2}}

e x p an d \frac{4 x y}{( x + 2 ) ^{2}}

e x p an d \frac{( - 1 ) ^{n} ( 7 n + 5 )}{( 5 n ^{2} - 4 n + 3 )}