化简 10(4log_{2}(40)+48log_{2}(1300))

解答

化简

10 (4 lo g_{2} (40) + 48 lo g_{2} (1300))

1080 + 10 lo g_{2} (625 \cdot 32 5^{48})

十进制

5178.13915 \dots

求解步骤

10 (4 lo g_{2} (40) + 48 lo g_{2} (1300))

4 lo g_{2} (40) + 48 lo g_{2} (1300) = 108 + lo g_{2} (625 \cdot 32 5^{48})

= 10 (108 + lo g_{2} (625 \cdot 32 5^{48}))

展开

10 (108 + lo g_{2} (625 \cdot 32 5^{48})) : 1080 + 10 lo g_{2} (625 \cdot 32 5^{48})

= 1080 + 10 lo g_{2} (625 \cdot 32 5^{48})

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