展开 pi(1+x^2)^2

解答

展开

π (1 + x^{2})^{2}

π x^{4} + 2 π x^{2} + π

求解步骤

π (1 + x^{2})^{2}

(1 + x^{2})^{2} = 1 + 2 x^{2} + x^{4}

= π (x^{4} + 2 x^{2} + 1)

打开括号

= π 1 + π 2 x^{2} + π x^{4}

= 1 π + 2 π x^{2} + π x^{4}

乘以:

1 π = π

= π + 2 π x^{2} + π x^{4}

改写为标准形式

= π x^{4} + 2 π x^{2} + π

e x p an d \frac{( n + 1 ) ^{2}}{4 n}

e x p an d \frac{n ( 3 n + 5 )}{3}

s im pl i f y (x) (1 - x^{2})

e x p an d \frac{1 - 2 ( x + h ) - 1 - 2 x}{h}

e x p an d 5 \cdot (2 x + 3) x + 54