展开 (sqrt(1+2ax))/(\sqrt[3]{1+3bx)}

解答

展开

\frac{1 + 2 a x}{3 1 + 3 b x}

\frac{1 + 2 a x ( 1 + 3 b x ) ^{\frac{2}{3}}}{1 + 3 b x}

求解步骤

\frac{1 + 2 a x}{3 1 + 3 b x}

乘以共轭根式

\frac{( 1 + 3 b x ) ^{\frac{2}{3}}}{( 1 + 3 b x ) ^{\frac{2}{3}}}

= \frac{1 + 2 a x ( 1 + 3 b x ) ^{\frac{2}{3}}}{3 1 + 3 b x ( 1 + 3 b x ) ^{\frac{2}{3}}}

3 1 + 3 b x (1 + 3 b x)^{\frac{2}{3}} = 1 + 3 b x

= \frac{1 + 2 a x ( 1 + 3 b x ) ^{\frac{2}{3}}}{1 + 3 b x}

e x p an d \frac{π + π e ^{- s}}{( s ^{2} + 4 ) ( s ^{2} + π ^{2} )}

s im pl i f y (3 - x - 1)^{2}

e x p an d (a^{2} + a - 1)^{5}

e x p an d (x^{2} - 9) e^{x}

e x p an d f (1, - 4)