展开 3(sin^6(θ)+cos^6(θ))+9sin^2(θ)cos^2(θ)

解答

展开

3 (sin^{6} (θ) + cos^{6} (θ)) + 9 sin^{2} (θ) cos^{2} (θ)

3 sin^{6} (θ) + 3 cos^{6} (θ) + 9 sin^{2} (θ) cos^{2} (θ)

求解步骤

3 (sin^{6} (θ) + cos^{6} (θ)) + 9 sin^{2} (θ) cos^{2} (θ)

使用分配律:

a (b + c) = ab + a c

3 (sin^{6} (θ) + cos^{6} (θ)) = 3 sin^{6} (θ) + 3 cos^{6} (θ)

= 3 sin^{6} (θ) + 3 cos^{6} (θ) + 9 sin^{2} (θ) cos^{2} (θ)

e x p an d x^{\frac{1}{3}} (x^{2} - 70)

e x p an d sin (t) u (t - 2 π)

e x p an d 2 x - 1 \cdot (x - 1)

e x p an d (x^{2} - 1) (e^{x})

s im pl i f y (x + 1 + 2) (x + 1 - 2)