展开 (e^x+1)(e^x-1)

解答

展开

(e^{x} + 1) (e^{x} - 1)

e^{2 x} - 1

求解步骤

(e^{x} + 1) (e^{x} - 1)

使用平方差公式:

(a + b) (a - b) = a^{2} - b^{2}

a = e^{x}, b = 1

= (e^{x})^{2} - 1^{2}

化简

(e^{x})^{2} - 1^{2} : e^{2 x} - 1

= e^{2 x} - 1

s im pl i f y (x - \frac{24}{x + 2}) (x - \frac{12}{x - 4})

s im pl i f y (x + 1 - 2) (x + 1 + 2)

e x p an d \frac{x ^{2} + 2 x + 4}{( x + 1 ) ^{2}}

e x p an d (2, - 4) y (- 3, 8)

s im pl i f y (- x + \frac{1}{2}) (- x - \frac{1}{2})