解答
展开 (x+23)12
解答
x12+18x11+2297x10+21485x9+1640095x8+424057x7+16168399x6+16216513x5+2563247695x4+1281082565x3+5121948617x2+512531441x+4096531441
求解步骤
(x+23)12
使用二项式定理: (a+b)n=i=0∑n(in)a(n−i)bia=x,b=23
=i=0∑12(i12)x(12−i)(23)i
展开求和
=0!(12−0)!12!x12(23)0+1!(12−1)!12!x11(23)1+2!(12−2)!12!x10(23)2+3!(12−3)!12!x9(23)3+4!(12−4)!12!x8(23)4+5!(12−5)!12!x7(23)5+6!(12−6)!12!x6(23)6+7!(12−7)!12!x5(23)7+8!(12−8)!12!x4(23)8+9!(12−9)!12!x3(23)9+10!(12−10)!12!x2(23)10+11!(12−11)!12!x1(23)11+12!(12−12)!12!x0(23)12
化简 0!(12−0)!12!x12(23)0:x12
化简 1!(12−1)!12!x11(23)1:18x11
化简 2!(12−2)!12!x10(23)2:2297x10
化简 3!(12−3)!12!x9(23)3:21485x9
化简 4!(12−4)!12!x8(23)4:1640095x8
化简 5!(12−5)!12!x7(23)5:424057x7
化简 6!(12−6)!12!x6(23)6:16168399x6
化简 7!(12−7)!12!x5(23)7:16216513x5
化简 8!(12−8)!12!x4(23)8:2563247695x4
化简 9!(12−9)!12!x3(23)9:1281082565x3
化简 10!(12−10)!12!x2(23)10:5121948617x2
化简 11!(12−11)!12!x1(23)11:512531441x
化简 12!(12−12)!12!x0(23)12:4096531441
=x12+18x11+2297x10+21485x9+1640095x8+424057x7+16168399x6+16216513x5+2563247695x4+1281082565x3+5121948617x2+512531441x+4096531441