|x^2-1|=3

Lösung

x^{2} - 1 = 3

x = - 2 or x = 2

Schritte zur Lösung

x^{2} - 1 = 3

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x^{2} - 1 = - 3 or x^{2} - 1 = 3

x^{2} - 1 = - 3 or x^{2} - 1 = 3

keine L \overset{o}{¨} sung or (x = - 2 or x = 2)

x = - 2 or x = 2

2 x + 1 \leq 0

\frac{x}{4} = x

f a c t or 15 y^{3} + 20 y^{2} - 5 y

f a c t or 6 y^{3} - 24 y^{2} + y - 4

s im pl i f y (3)^{4}