s^2+8s+12=0

解

s^{2} + 8 s + 12 = 0

s = - 2, s = - 6

解答ステップ

s^{2} + 8 s + 12 = 0

解くとthe二次式

s_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 12 = 4

s_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 1}

解を分離する

s_{1} = \frac{- 8 + 4}{2 \cdot 1}, s_{2} = \frac{- 8 - 4}{2 \cdot 1}

s = \frac{- 8 + 4}{2 \cdot 1} : - 2

s = \frac{- 8 - 4}{2 \cdot 1} : - 6

二次equationの解:

s = - 2, s = - 6