faktorisieren 2x^3+x^2-13x+6

Lösung

faktorisieren

2 x^{3} + x^{2} - 13 x + 6

(2 x - 1) (x - 2) (x + 3)

Schritte zur Lösung

2 x^{3} + x^{2} - 13 x + 6

Wende den rationalen Nullstellentest an

= (2 x - 1) \frac{2 x ^{3} + x ^{2} - 13 x + 6}{2 x - 1}

\frac{2 x ^{3} + x ^{2} - 13 x + 6}{2 x - 1} = x^{2} + x - 6

= (2 x - 1) (x^{2} + x - 6)

Faktorisiere

x^{2} + x - 6 : (x - 2) (x + 3)

= (2 x - 1) (x - 2) (x + 3)

f a c t or a^{2} + 2 a - 8

f a c t or (p + q)^{2} + 4 (p + q) + 4

f a c t or x^{2} - \frac{49}{25}

2 x (4 - x) - \frac{3}{5} (15 x - 7) = \frac{1}{2} (4 - 6 x) - 2 x^{2}

s im pl i f y \frac{5 x ^{- 2}}{3 x} \cdot \frac{2 y ^{3}}{x ^{10}}