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Frequently Asked Questions (FAQ)
What are the solutions to the equation 4y^2-y+2=0 ?
- The solutions to the equation 4y^2-y+2=0 are y= 1/8+i(sqrt(31))/8 ,y= 1/8-i(sqrt(31))/8
Find the zeros of 4y^2-y+2=0
- The zeros of 4y^2-y+2=0 are y= 1/8+i(sqrt(31))/8 ,y= 1/8-i(sqrt(31))/8